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Single Transformer Inverter/Charger Circuit

The post explains how to build an innovative inverter circuit with a single transformer that works both as an inverter and a battery charger transformer, Let's learn the details from the following discussion.

The Circuit Objective


Though you may find many inverters having an integral battery charger, the section will mostly employ a separate transformer for implementing it.

The following article describes a unique design which utilizes the inverter transformer for power inverting as well as for charging the battery.

The circuit diagram below shows a design where a single power transformer is used for inverting purpose as well as for charging the battery when mains is present.

The good thing about the circuit is that the transformer doesn't employ separate winding for this, rather works with the same input winding and reverts DC to the battery with the help of a few DPDT relays.

The circuit can be understood with the following points:

How the Circuit Functions


The inverter section can be easiy recognized in the diagram, R1 to R6, including the T1 and T2 forms a general astable multivibrator circuit for producing the required 50 or 60 Hz pulses.

These pulses drive the mosfets alternately which in turn saturate the transformer by switching the battery voltage in it.

The secondary of the transformer generates the corresponding magnitude of AC which is finally used for operating the connected appliances.

The above configuration suggests an normal or ordinary inverter operation.

By adding a couple of DPDT relays in the above discussed operation, we can force the circuit to charge the battery in the prsence of an AC mains source.

The coils of the two relays are powered through a capacitive low current compact power supply, involving C6, C5, D1----D5.

The above circuit is connected to a mains AC source, this source is also connected to RL1 poles.

The second relay RL2 is wired up with input winding of the transformer.

In the absence of mains AC, the position of the relay contacts are in the N/C as shown in the figure.

In this position the mosfets get linked with the transformer input winding, and the battery with the circuit so that the inverter starts oscillating and the output appliances gets the AC power from the battery.

In the presence of mains AC the relay coils instantly get the required DC power and the contacts activate.

RL1 activates and connects the mains input to the transformer, the appliances also get connected with the mains AC in the process.

Also due to the action of RL2 the mosfets get disconnected from the transformer, while the the lower tap connects with D6.

Since the center is already connected to battery positive, the inclusion of D6 provides a half wave rectified voltage to the battery, which is effectively filtered by C3 so that the battery is able to get the required sufficient charging voltage.

The above charging process continues until mains is present, so it should be monitored manually. When mains fails, the action reverts into inverting mode without interrupting the appliance operations and by using a single transformer for both the operations.

C4 makes sure that RL1 always activates a shade later than RL2 for safety reasons.





CAUTION: THIS CIRCUIT IS DEFINITELY NOT RECOMMENDED FOR THE NEW HOBBYISTS, IT'S SUITABLE ONLY FOR THE EXPERTS. IF YOU ARE A NOVICE AND INTERESTED TO TRY THIS.... BUILD IT AT YOUR OWN RISK.

Parts List


R1, R2 = 27K,
R3, R4, R5, R6 = 470 Ohms,
C1,C2 = 0.47uF/100V metallized
T1, T2 = BC547,
T3, T4 = any 30V, 10amp mosfet, N-channel.
C3 = 47000uF/25V
C4 = 220uF/25v
C5 = 47uF/100v
C6 = 105/400V
R7 = 1M
D1---D5 = 1N4007
D6 = 1N5402
RL1, RL2 = DPDT, 400 OHMS, 12V, 7 AMPS/220V
Transformer = 12-0-12V, current as per requirement.

For only inverter design please refer to this ARTICLE

Need Help? Please leave a comment, I'll get back soon with a reply!




Comments

  1. Acquiring 24V from 12V is difficult and is not recommended, because the transformer can become hot.

    Wattage rating can be controlled by controlling the battery current through some circuit stage.

    ReplyDelete
  2. DEar sir,
    Can i use a 10 A relay instead of the 7 A one used here

    What precaution should be taken in order to safeguard the entire circuit before applying the ac mains to transformer's primary ?

    And one more doubt sir
    What does the connection (which seems like inductor coil )in the upper circuit means ? I realize that these are the connections across two relay pins and the upper circuit is the power feeding circuit for the relays. But i can't understand the 2 pins that i specified here. Please help me sir. I am not at all familiar with relays. Hoping your reply very soon sir......

    ReplyDelete
  3. Dear Arun,

    Use a 100 watt bulb in series with one of the input mains wires for safety.

    The inductors are the relay coils, a relay cannot be activated unless its coils are energized therefore these coils are supplied through the capacitive power supply shown at the upper section of the diagram.

    ReplyDelete
  4. ....you may refer to this post for knowing more about relays:

    https://homemade-circuits.com/2012/01/how-to-understand-and-use-relay-in.html

    ReplyDelete
  5. Sorry for disturbing you again sir. But what to do.... I have to be completely free of doubts before going for the design..... This time i am also coming with another doubt which may feel silly to you, please dn' t neglect it since i am not having deep knowledge in Electronics, but i like it.

    I have a 300 W 12 V transformer having 4 thick windings at primary and 5 at secondary. I know it is a multi-tap one. But don't know how to wire them to suit for the single transformer inverter design.. Please help me......



    How can i link the images with the comments in this blog ?

    ReplyDelete
  6. You can connect the 220V wires to mains and measure the tap voltages with a multimeter, in this way you would be able to figure out the tap values.

    ReplyDelete
  7. you can upload the images on any free image hosting site and provide me the link.

    ReplyDelete
  8. Sir that was not enough..... I need a better suggestion.......
    My transformer is a locally made one. No markings ( even no separate colors for wires ) are there. The only thing that i could see that some set of the terminal wires are thicker than other set. From basic calculations of transformer design, i think the wires to bear large current are of secondary ( 300 W/ 12V ) and they have to be thick enough than the primary. Am i right ? If not please correct me.....
    I am in a little bit confusion that how to connect the neutral and earth lines of ac mains into the transformer if it has 5 primary terminals as i calculated..... Please help me sir... Can you please suggest the exact connection schematics.....
    Since it is an ac transformer, i willn't be able to measure the tap voltages exactly without a brige type rectifiers. Taking each tap voltage by changing the polarities supplied to the rectifier will be very time consuming..
    I couldn't upload the images of the transformer.... SO PLZ HELP ME

    ReplyDelete
  9. you won't need a bridge rectifier at each tap for checking, you can do it with your meter on AC 220V range.

    you can also check the taps by measuring their resistances...the one which gives the highest resistance can be assumed to be the mains input winding, connect a 100 watt bulb in series which testing with mains for avoiding possible hazards.

    ReplyDelete
  10. Very nice circuit sir.
    Can i use a 300 W transformer in this circuit ? How much high will be the currents in both terminals ? Can i use the formula P= IV for its calculation. If i am doing so i will get maximum current
    In primary : 1.304 A and
    In secondary : 25 A........ Is that will happen ?

    If so, that diode (IN5402) used in Charging section sufficient to overcome this high amperage ?
    What about the diodes at the primary if i am using the inverter to be run on a 300 W load. Reply me soon plz....... Sorry for the bad english...

    ReplyDelete
  11. Thanks Ramsree,

    You can use P = IV, 25amps is right but that might be too high for the battery, because as per rules the ideal charging current should be 1/10th of batery AH, so we may have to upgrade the circuit with an additional current limiter circuit and also some modification in the relay wiring.....

    ReplyDelete
  12. What modification you mean sir ? How can i modify this circuit to charge a 60 Ah battery bank effectively ? Can i use your one of previous post on ' 3 stage smart battery charger for 12 V ' with this.circuit ? What modifications to be done sir ?

    ReplyDelete
  13. Dear sir,
    Can you please give a model current limiting circuit to fullfill my need ? Can i have it to be used prior to the rectification section ? Thereby i can avoid using high ampere diodes there. that is why

    ReplyDelete
  14. Another doubt too sir,
    If i am using battery rated below 100 Ah along with the current limiting circuit , will it be possible for the inverter to run maximum load that i am expecting with ?

    ReplyDelete
  15. a simpler approach would be to add a calculated current limiting resistor in series with D6

    ReplyDelete
  16. As mentioned in the previous comment, the series resistor with D6 will not interfere with inverter power outputs, it will work with the specified full capacity

    ReplyDelete
  17. Thank you so much for this post. I will like to give you feed back after I complete the work and I will also prefer to know about circuit diagram.

    Kindly, let me ask this question.
    1. Is it possible to use this circuit with 24volts battery without any damage to the cell of the circuit?

    ReplyDelete
  18. Hi Swag,
    is it possible to use transformer with 6v - 0 - 6v and if yes what will be the output of it?

    Thanks.

    ReplyDelete
  19. Yes, 24V can be used, provided the transformer and the relays are also rated at 24V.

    ReplyDelete
  20. Hi Adeleke,

    it would work with a 6V battery...output would be equal to the output rating of the transformer, if it's 220v then it would generate 220V

    ReplyDelete
  21. Hai sir,
    Can i ask you something......
    What modification to be done to the present circuit if i am using high current transformer ??
    A series current limiting resistor alone will not do this purpose i think. What extra things to be added to the oscillation section to prevent ir from accidental damage due to high current flow. Also i want to know the necessary changes to be made on relay wiring also. Please try to REPLY MY ALL QUESTIONS SIR

    ReplyDelete
  22. Hi Venkitesh,

    I'll try to find some appropriate solution and update it soon.

    ReplyDelete
  23. Hai sir it is again prithviraj speaking.....
    A serious doubt is now disturbing me....
    As per your suggestion, the inverter o/p after successful testing can be connected directly to the ac wall outlet. But in this inverter schematics, the relay coils are actuated by the ac mains. So if i am gonna follow my strategy, will the relay actuate on getting supply during inverter operation and continously turn ON and OFF ?????

    ReplyDelete
  24. Hi Prithviraj,

    You are right, the above inverer cannot be inserted in the wall socket, because the relays would start vibrating ON/OFF due to the particular configuration employed in the circuit.

    ReplyDelete
  25. Thank you Sir for replying me fast. Now i want to know whether any modification can be done to the present structure to suit my need or can you suggest any other design for me. I know i am disturbing you a lot. But what to do, i willn't get a better sleep if the problem is kept unsolved....
    I am not at all interested in connecting appliances directly to inverter terminal out, because it will cause discomfort in turning a particular device on at a room

    ReplyDelete
  26. I am sorry Prithviraj, there's no possible way out with the above circuit We can consider a manual option using DPDT switch for the changeovers.

    ReplyDelete
  27. Sir i think it is possible to solve the issue by any of these,,,,,,,,
    What about using a descriminator circuit to distinguish the sinewave from the square wave( which is produced by the inverter ) and actuating the relay only on sine wave, i.e, during mains is present.
    Another way i think, is to slightly make a change to the existing frequency of square wave ( which is 50 Hz ) and thereby identifying the power on condition by counting frequency of the incoming signal to the relay coil fed.

    But i don't know how this will take effect or will be effective and also don't know how to arrange these modifications. ..... So can you please help me

    ReplyDelete
  28. I don't think that would help, in that case when the mains comes back it will first clash with the inverter AC and cause undesirable things to happen, a fire, a blown fuse etc. because once the the inverter AC gets into the wall socket it's bound to mix with the mains AC unless a DPDT is employed for isolating the respective ACs manually

    ReplyDelete
  29. Hellow sir, how did you calculate the value of resistors and capacitors incorporating the AMV stage of two.coupled transistors. I have to place available and suitable components there

    ReplyDelete
  30. Hello Rishikesh,

    you can use the following formula
    f = 1/1.4CR. where C = C1 = C2, and R = R1 = R2

    R will be be in OHMs and C in FARADS

    ReplyDelete
  31. If the relay fails, won't it be dangerous to the inverter?

    ReplyDelete
  32. yes it could be dangerous, we can include a safety fuse for that in the circuit

    ReplyDelete
  33. hello Swagatam,
    I interested in this circuit diagram but being novice, I'm finding difficult to understand the connect basically the operation of dpdt relay.
    how many relays are required in this circuit diagram and how do I connect it pls
    Thanks

    ReplyDelete
  34. Hello Agbadu,

    If you are new in the field please do not try this circuit, it's strictly for the experts.

    2nos DPDT relays are used in this circuit.

    ReplyDelete
  35. but pls sir can you explain the charging section relay connection for me
    also can this circuit be converted to 2.5kva, if yes how?
    Thanks

    ReplyDelete
  36. I have already explained it in the article, if you have a specific doubt you can ask it.

    if the above basic model is confirmed then it can be modified for 2kva also.

    ReplyDelete
  37. Sir, tanks for the post
    Pls I don't get how to connect RL2 to the two mosfet since one Relay is specified for the two I can only connection one successfully. Pls help explain

    ReplyDelete
  38. RL2 could be a DPDT type relay having two sets of contacts but a single coil controlling both the contacts simultaneously

    ReplyDelete
  39. Thanks, try to DPDT type Relay

    ReplyDelete
  40. Hi sir, I'm unable to lay me hand on DPDT type relay, can I use 4 SPDT relay instead of DPDT relay, pls quick reply will be appreciated, thanks

    ReplyDelete
  41. Hi kolley, yes that will also do.

    ReplyDelete
  42. Hi Swagatam, thanks for the he'll so far. Pls which capacitor can I use instead of C1,C2,C3 and C6 am unable to get those capacitors here. Thanks

    ReplyDelete
  43. Hi Kolley,

    the capacitor values cannot be changed, so you'll have to use as suggested.

    the ones which are polarized need to be electrolytic while the others metallized polyester type.

    please note that this project is not for the newbies and requires expert knowledge in the field...the circuit has the potentials of causing fire hazard and explosion if not done correctly.

    ReplyDelete
  44. Hello sir, I just finished testing the circuit,am having two problem,1.the mosfet get hot immediately I connect to d battery power and the wire that come from transformer spark to the extent of getting burnt when I connect it to + side of d battery.2 the is turns on and off repeatedly when I connect it to AC supply pls what can I do to rectify these problems.thanks. Pls a quick reply will be appreciated

    ReplyDelete
  45. Kolley, you have surely done something terribly wrong with the connections which I cannot diagnose from here.

    remove the relays and make the inverter separately first, as given in this article:

    https://homemade-circuits.com/2012/09/mini-50-watt-mosfet-inverter-circuit.html

    use a separate transformer for charging the battery, the above circuit is not suitable for newcomers.

    ReplyDelete
  46. Dear Swagatam ,
    I had a home inverter which i was using for charging my car battery. One day by mistake i left battery charging wires on floor ,after that i see no voltage in battery charging wires. I checked the main Ac fuse of inverter ,it is ok but one warning sticker is there on inverter that avoid shorting of charging wires other wise its DC fuse will blow . Kindly give some information on indian make inverters DC fuse location . Inverter make is Reliable . It has only one PCB on charging side supply is going to charging wires through heat sink having 4 MODFET each side.

    ReplyDelete
  47. Dear Hamza,

    I am sorry, it'll be difficult to provide a proper suggestion regarding this since the configuration may be different for different inverters and I haven't yet opened the brand that you have mentioned.
    However a fuse in any inverter will be always in series with the battery line and also could be with the output AC line, you can investigate these two positions, I am sure you would easily locate a few across these lines.

    ReplyDelete
  48. the relays are 12V , in Fig. it is directly connected to mains, pls explain

    ReplyDelete
  49. the right hand side contacts are connected with mains, the coils are connected via C6

    ReplyDelete
  50. Hi,
    This question is not related to the post. Pls reply, I recently purchased a 12-0-12 transformer, and as I measured the V between both ends,it shows 0 V ( not 24V) and centre tap to each end it shows 12 V each. So what type winding is used in it?

    ReplyDelete
  51. may be the center taps are split, join the two center taps together you will then see 24V across the outer taps

    ReplyDelete
  52. Hi
    No, the center tap is OK, because there is a continuity between both ends.

    ReplyDelete
  53. Hi, that's impossible, if the individual winding are showing 12V (from center to out), the outer taps will show the sum of the two winding.

    something may not be correct with your meter or measuring procedure.

    make sure the meter is selected in the AC range.

    you may also check the continuity of the winding using the diode range in the meter.

    ReplyDelete
  54. ....another issue could be the internal winding polarity of the trafo, which could be incorrectly wound.

    ReplyDelete
  55. I have a China inverter and a12v battery charger plz give me some circuit or understood me that if light is gone then automatically my battery give me back up and if light comes again then start battery charge automatically
    I hope u understand my question

    ReplyDelete
  56. you can try the following circuit for implementing the required automatic changeovers:

    https://homemade-circuits.com/2014/06/how-to-convert-inverter-to-ups.html

    ReplyDelete
  57. Sir, thanks a lot for your work here..

    There's just one thing I'm a bit confused about in this circuit..

    220VAC enters the bridge Rectifier from the mains input,, 220VDC comes out.... But the relays are rated for 12VDC

    I'd like to know which of the components in the circuit does the job of limiting the 220VDC to the 12VDC required by the relay coils.... Thanks

    ReplyDelete
  58. Banimz, the capacitor output has very low current content therefore the 300V DC will automatically drop and adjust to the relay coil voltage.

    no external limiting agent is required for this

    ReplyDelete
  59. Pls, how many mosfet of irfp 250 did I need to combine on my inverter to give 1000wat
    Regards

    ReplyDelete
  60. Thanks a lot....

    Speaking of that capacitor.... I can't find a ceramic capacitor of 1uf anywhere near... But I do have an electrolytic capacitor of 2.2uf....

    Will this affect the circuit???

    I'm talking about C6...

    ReplyDelete
  61. Is the capacitor C6 a very crucial part of the circuit? Or can I leave it out?

    ReplyDelete
  62. Pls specify the voltage/amp specs of the mosfet, it will help me to calculate the parameters.

    ReplyDelete
  63. C6 is a 105/400V PPC capacitor, it's abundantly and easily available in the market.

    ReplyDelete
  64. without C6 the relays will not operate.

    ReplyDelete
  65. Thanks so much for the quick respond
    The mosfet voltage is vdss 200v and 33A
    Regards

    ReplyDelete
  66. Okay, thanks.... So now I've gotten a 105/400V capacitor for C6..... And I've finished constructing the circuit...

    Now I noticed something. If I connect power to the circuit before connecting a relay ,,,, the relay will trigger...

    But if I connect the relay before turning on the power,,, the relay won't respond..... Upon testing, I discovered that just about 5V gets to the relay if it is connected before the power turns on.... Almost as if its acting as overload on the circuit......

    What could be the cause of this and how can I rectify the problem??

    Oh, also, both relays don't trigger at the same time,, whether power is connected beforehand or not..... Only one works at a time,,,, if I connect one and it triggers,, the other won't trigger......


    Eagerly awaiting your response...

    Thanks a lot for everything

    ReplyDelete
  67. 3 mosets on each channel would do.

    but first you should try with single fets and try to accomplish a minimum 300 watt output

    ReplyDelete
  68. Sir, the circuit is now working well.... Except for one minor issue.... My relay coils are 90 ohms instead of 400...... Thus, the current this circuit is producing is too low to power both of them together..... .....

    How can I increase the current in this circuit?? Should I reduce the 1M resistor??? Or something else? Eagerly awaiting your response.. Thanks a lot

    ReplyDelete
  69. Thanks so much
    Pls can u tell me hw u calculate it, I mean the formula you used to cal the wattage of the mosfets.
    Thanks

    ReplyDelete
  70. The relays that you have are not of good quality, they might be having a very low resistance coil, in that case you should think of using a 12V AC/DC adapter instead of the C6 power supply.

    The connections will be identical, the 12V from the adapter will connect with the relay coils including D5, C4....

    D1---D4 and C2 may be removed.

    The input of the adapter will need to be connected across the points indicated "mains input"

    ReplyDelete
  71. You can use an adapter as stated in the previous comment...

    ReplyDelete
  72. multiply its voltage rating and amp rating and reduce it to 25% for safety.

    ReplyDelete
  73. Thanks so much sir...

    I was eventually able to get the required current and voltage to drive my relays by using four of the C6 capacitors in parallel.....

    Its all working now.. Thanks a lot sir

    ReplyDelete
  74. Sir thanks so much for your help so far,
    Please help me, I build an inverter using IC SG3524 the inverter is working fine on some appliances but won't work on some like small or big fan, small hair clipper and a desktop computer, pls what can I do to make it work on all appliances?
    Regards

    ReplyDelete
  75. I think I have already answered this in your previous comment.....

    ReplyDelete
  76. Sir pls answer me here,I can't find the link to the previous comment again on my computer
    Or if u can provide the link for me I will be happy
    Thanks

    ReplyDelete
  77. Hi Kolley,

    It could be due to insufficient battery power or trafo wattage....measure the output voltage of the inverter when you connect those loads, if you find the voltage dropping would confirm an inadequate battery current or transformer wattage.

    ReplyDelete
  78. Thanks for the quick responds
    The output voltage before those load is close to 240 but after connecting the load it drop to 220, which I think should be sufficient but still it won't power fan and clipper

    ReplyDelete
  79. 220V is more than sufficient, that's weird, can't diagnose without seeing it practically...just check if both the power transistors are conducting uniformly, you can do it by connecting car headlight lamps in series with the transformer taps which are linked with the power devices....

    ReplyDelete
  80. hi Sir Swagatam

    i dont know much more about electronics basics, But i want to make this ups for my DSL Router and Laptop Charger , I understand the circuit, but DPDT Relay is confusing me ,

    I have found that DPDT Relay have 6 points , 2 for coil, 2 for NC and 2 for Com,
    Can you Please mention that how to use relay in this circuit and what is treatment for coil points,

    If you Please explain the working of R1 and R2 while marking on a picture of DPDT so that i may knwo which points of relay i have to use and which of them are to be leave as it is ,

    Please help me ,

    Thanks

    ReplyDelete
  81. Hi Waqar,

    I don't think you would require such a complex inverter circuit for a modem, charger application, you can try the following design:

    https://homemade-circuits.com/2013/03/simple-dc-ups-circuit-for-modemrouter.html

    ReplyDelete
  82. yes, C3 should be 4700uF....... and not 47000uF

    ReplyDelete
  83. hello...Mr.Swagatam

    I want to make 1200w inverter but problem is in charging circuit I can't use relay for it because it take 100a in inverter mode and 10 in charging mode

    I use 4xIRFZ44N mosfet
    can I use MOSFET reverse diode in charging mode ????

    ReplyDelete
  84. hello janak, if you are referring to the above circuit, it cannot be used without relays....it would work only with the relays connected in the indicated manner

    ReplyDelete
  85. sir,
    could you help me for making a simple inverter for lighting a 18w CFL ?
    i have a 12V 9ah battery and 12-0-12 3A transformer.
    Hope you may help me
    Arun

    ReplyDelete
  86. arun, you can try the following circuit:

    https://homemade-circuits.com/2012/09/mini-50-watt-mosfet-inverter-circuit.html

    ReplyDelete
  87. Ya i found it..
    can i use IRF540 or IRFZ44 for T3 and T4
    of the circuit on the link???

    ReplyDelete
  88. What is the output power of this ckt?

    How much watts can it handle?

    ReplyDelete
  89. it will depnd on th trafo, battery and mosfet ratings

    ReplyDelete
  90. Can it handle a table fan motor load of 25-30 watts , if I use 12v 7ah battery and 12-0-12 ,1 A transformer

    ReplyDelete
  91. you will need a 9-0-9/5amp transformer, and a 12V 7AH battery for operating your fan properly

    ReplyDelete
  92. Hello Mr. Swagatam,
    Please can I use this circiut for 24volts and at the same time use it for TV and other equipment in the house.

    ReplyDelete
  93. Hello Mr. Adelke,

    No 24V cannot be used for this design since it employs a 12-0-12V transformer.

    ReplyDelete
  94. Hi Mr. Swagatam, very grateful for your response.
    Please, if I want to convert it to 24volts is it possible and if YES, what are things that I needed to change from the circuit.
    Thanks.

    ReplyDelete
  95. Hi Mr. Adelke, for that you might need a 20-0-20 transformer and a 48V battery

    ReplyDelete
  96. sorry, the battery would need to be 24V not 48V....and the 470 ohms will need to be changed to 1K, while the 27k resistor calculated appropriately

    ReplyDelete
  97. Thank you Mr. Swagatam, very grateful for impacting others with your idea and knowledge.
    Thank you.

    ReplyDelete
  98. If battery 48v..transformer need ?

    ReplyDelete
  99. for the above design it should be 0-48V

    ReplyDelete
  100. Hi Swagatam? What controls the charging time so as not to overcharge the battery? Thanks.

    ReplyDelete
  101. Hi Joseph, over charge cut off is not included in this design but since the battery is charged only upto 70% it won't harm the battery

    ReplyDelete
  102. Hello brother, as i look the diagram i see that battery charging system is half wave rectification when relay switches by mains 220v doesn't this damage the battery? Your design is simple than mine i designed using microcontroller. But i am still looking for the best charging method with cutt off for a 200Ah battery. I am using irf3205 mosfets and a 600w transformer. Any suggestion ? I will appreciate! Thanks and your posts are always amazing and informative

    ReplyDelete
  103. Thank you Syed, Half wave charging will not affect or harm the battery in any manner, you can improve the DC by increasing the filter capacitor value to some higher value....for example a 10,000uF could be tried t enhance the DC quality for the battery.

    ReplyDelete
  104. Why there is no surge protection that is done because of the capacitor no polarized like 2.2uf 400V between the mains terminals LIVE and NEUTRAL

    ReplyDelete
  105. the load here are the relay coils which are strong enough to neutralize the initial switch ON surge...

    ReplyDelete
  106. Thanks Swagatam this means alot. One more question if you don't mind "Do you think that two IRF3205 will do the job for 500-600W transformer with 200Ah battery." I'll share my design with you soon.

    ReplyDelete
  107. You are welcome Syed, yes it will work, but the heatsink will need to be adequately dimesioned and if possible cooled with a fan...

    ReplyDelete
  108. Hey Dear, Did you add current limitation adjustments to the above circuit ever. Let me know. I think the design is wonderful. So we should work on it. Kindly share the link if you already posted about adding a limiter to this circuit.

    ReplyDelete
  109. Hey check out this. I added regulation to your circuit:
    imgur.com/gallery/A7gED

    ReplyDelete
  110. current limitation for battery charging??
    it could be done through a series LM338 IC configured in the current limiting mode

    ReplyDelete
  111. Hey Swagatham there let me know your E-mail. So i can send you my design which has better charging and cuttoff option

    ReplyDelete
  112. Hi Syed, you can send it to admin @ homemade-circuits.com

    ReplyDelete
  113. Good Evening Sir,
    Sir, can I replace C5 (that is 47uF/100v) with anyone bellow the or little above the specified on?
    And for C6 (that is 105/400V) with 104/630v or 104/250v.



    Thanks you Sir.

    ReplyDelete
  114. Aminu, the value needs to be little bigger, 105 or 104 will not be suitable, you can try 10uF/250V

    C6 cannot be less than 105, otherwise the relays will not operate, in fact you must use two 105 in parallel

    ReplyDelete
  115. Hy I m bravo pls I don't see dat 0.47uf 100v cap in my area pls can I use 0.33uf electrolytic or pls give me any close value I can use anD for that relay I whan to use small 12v 500ma trafo to power d coils and the C3 I get 4700uf by 16v will all this be ok pls help me out. Tnks

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  116. Hi, 0.47uF, and 27K together are supposed to determine the 50Hz freq, 0.33uF will reduce the frequency....in that case you might have to increase the 27K to 33K or 39K to correct the frequency to the 50Hz level

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  117. Tnks for the reply
    another question sir, (1) pls what will be the value of r1 nd r2 if I use 0.22uf electrolytic cap for c1 nd c2 to get the 50Hz, (2)what value of zener diode can I use to protect my mosfet from damage. tnks

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  118. 1) you can use the followin softare for calculating them

    https://homemade-circuits.com/p/transistor-astable-multibivrator-amv.html

    use 1/50 = 0.02 for the time period slots

    2) you can use 12V zeners although it won't be required if the supply is 12V

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  119. I get 474j/250v for c1 nd c2, will it be ok for the same value of r1 nd r2 which is 27k
    (2) What if I use 1n4007 to protect my mosfet?
    Tnks

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  120. it will do.

    mosfets already have built in freewheel diodes there's no need of an external diode.

    anyway 1N4007 will not be enough....you can try 1N5408 instead for your satisfaction.

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  121. Hi Swagatam, thnx for the huge efforts, very helpful. I've a question plz, I am troubleshooting an inverter, it's not charging the battery anymore, the output goes to the battery is 7.5v, which should be no less than 12v. Plz what could be the reason for that?
    Thanks in advance.

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  122. Thanks Taher, please disconnect everything that's connected with the transformer or the source of the supply, and check whether it reads around 14/15V or not, if yes then the problem could be somewhere in the adjoining electronics or controller which will need to identified appropriately....if the source shows less voltage then it will need to be replaced with a new one.

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  123. Hello sir please c1 c2 c5 can I use 100v 10uf because I can't find the real values

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  124. Please sir can I use100v 10uf in the place of c1 c2 c5 because I can't find the real values in my area

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  125. I would recommend to do exactly as specified in the diagram, any other values can be dangerous....for C1/C2 the values can be slightly changed, for C5 also the uF value can be changed but it must be strictly 400V rated

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  126. Hi sir, I have successfully completed the project, but I just wish I could increase the power of the inverter through mosfet, can I use six mosfet in parallel in this circuit instead of two?

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  127. That's great Frank, yesy ou can use 6 or more mosfets in parallel for increasing the power handling capacity along with the trafo and battery which will need to be equally upgraded

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  128. Hie Sir
    Is the polarity of C5 correct?

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  129. Hi Francis, sorry it's a mistake, please connect the positive lead with positive of bridge....

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  130. I have just constructed a similar inverter /charger but for the oscillation I used SG3524 ic. When I powered the inverter it worked great and when I plugged the AC mains it stopped inverting and stated charging the battery. But when disconnected the mains, I heard a continuous clicking sound from the relays and powered off the inverter but mosfet were shorted. Replaced mosfets again did the same but am sure I labled my relays correctly and I just switched the relays and no problem now worked. JUST DON'T KNOW HOW?

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  131. It will need to be examined carefully by switching the operations repeatedly, it will be difficult to judge without a practical test

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  132. Is there any problem if i overlap the winding of the transformer because i am making the transformer my self

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  133. Can i use 12-0-12 1 amp transformer and 4 ampere transistor for working 15 watts soldering iron

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  134. yes, the efficiency will be greatly affected.

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  135. The transistor heats up when i use ferrite transformer but when i use iron core it didn't get heatup at all. The ferrite transformer i use is got from from a old 120w inverter i am only using your Oscillator section of your circuit

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  136. If i use 2n3055 transistor instead of mosfet do i need to change the resistor

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  137. ferrite trafo will require a high frequency in the order of 20kHz, for iron core it is just 50Hz which is not compatible with ferrite core trafo

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  138. you will need to add additional driver stage as this

    https://homemade-circuits.com/50-watt-inverter-might-look-quite/

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  139. I have 600 va ups transformer but i dont know its secondary winding there are so many wire. How can i identify this??

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  140. Could you identify the primary winding which is supposed to be connected with the mains AC?

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  141. Sir i know the 12-0-12 winding detail what i need is the coils connected to ac mains

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  142. Elec, take another 12-0-12V known transformer, connect it to AC mains and feed its 12-0-12V AC to your UPS transformer's 12-0-12V wires, now check randomly across the output wires to find which one gives the accurate 220V, or 230V

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  143. Thanks for helping now i got the right winding
    If i want 500 watts from 12v 7ah battery how much amp transformer is needed

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  144. getting 500 watt from 12V/7AH is not possible...you will need a 200 AH battery for that

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  145. Hello Mr Swagatam. I very much appreciate your posts. Coming for years. I have to help with an inverter scheme for this pump. What scheme do you recommend? Thousands of thanks. Excuse me for my bad english. Please email me gogutu68 @ gmail.comfile:///home/probe/Desktop/pompa_es_2_dr_web.png

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  146. Thank you gelu, the shown link is not working in my PC. and also you will have to provide the technical specification of the motor in detail so that I can suggest you the right circuit

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  147. If you do not see the details, please tell me where to upload the pictures. Thanks again

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  148. the links which you are trying to send can be visualized only by you in your PC, it cannot be visualized by me or anybody else.

    You can send the specifications in written, that will be enough, image is not required.

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  149. Technical data
    maximum head MCA 5,7
    maximum flow cm/h 2,7
    power supply v/hz 230/50hz
    fluid temperature grdC 2-95
    ambient temperature grdC 0-40
    storage temperature grdC -20-70
    mahimum percentage % 40
    ECM equipment regulations cf EN 610-3-2/EN 61000-3-3/EN55014-1/EN55014-2
    Ferroli Energy Saving (ES) 25-60 /180 is an eficient electronic glandlles pump driven by a permanent magnet synchronous motor,fitted with frequency (inverter technology) The pump body is made of cast iron treated by cataphoresis to withstand the corosive action of the condensate.
    TECHNICAL SPECIFICATION UM lt it 25-60 / 180

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  150. Gelu, I only need the voltage and wattage of the pump, and whether it is a DC or AC, please provide these info, the voltage seems to be 230V AC, so just provide the wattage...

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  151. Thank you sir for helping by posting circuits . How much is the current rating of the transformer if I want to charge 24v 18ah battery ?

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  152. Hi Nikhil, you can use a 24-0-24V/3 amp transformer, make sure the filter capacitor is rated at least 6800uF/50V

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  153. Ok thank you Sir . And Sir I am using eg8010 as inverter section , so how can I connect both battery and H bridge configuration in transformer .

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  154. sorry, it can be done only with the above shown configuration, other configurations may not work as inverter/charger using a single transformer.

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  155. hi Sir, I need pure sine wave inverter without microprocessor

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  156. Hi Sunshine, I have explained many of them in this website, you can find them here:

    https://www.homemade-circuits.com/category/dc-to-ac-power-converters/

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