Skip to main content

220V SMPS, Buck Converter - 5V, 12V

The presented article explains a simple 220V to 5V, 12V, 24V buck converter or an SMPS circuit using the IC VIPer12A from STMicroelectronics. The circuit uses negligible number of external components yet is able to operate directly from mains AC input.

The Buck Converter Design


Looking at the given circuit diagram we see that the input stage incorporates a surge limiting resistor which quite acts like a fuse, a diode for rectifying the AC, and an LC filter network for further filtration of the DC riples.

The LC filter employed here ensures better DC stabilization and enhanced EMI response.

The capacitor Cin1 may be introduced for further reinforcing the EMI functionality.

The IC VIPer12A becomes the main PWM processor device which single handedly performs the entire buck conversion in the circuit.

Main Features


The main specifications of the configuration may be understood as follows:

  • AC input voltage Vinac 80 - 285Vac

  • Output current Iout 30mA

  • Output current Iout 250mA

  • Output voltage Vout1 +24±10%V

  • Output voltage Vout2 +5V±5%

  • Switching frequency 60 kHz

  • Output Power ~ 1W

How it Works


The circuit facilitates two outputs, rhe 24V output is achieved through a buck converter configuration while the 5V output via fly back mode.

The feedback voltage to the IC is acquired from Vout1 for the required regulation of the output, this supply is also applied to the IC Vdd pin.

The above wiring becomes possible by using a single high voltage diode and just one capacitor, to be precise D1 and C3, making the connections and costing much simpler.

The employed inductor L consists of two windings which are coupled across with each other over a common ferrite core.

The winding are done through appropriate turn ratios, where N1 = 200 turns and N2 = 60 turns. Both these are wound over a PANASONIC ELC10D152E ferrite core material.



Zener diodes z1 and z2 are installed in order to safeguard the outputs against over voltages.

A dummy load resistor is fixed across Vout1 so that appropriate regulation can be executed over both the outputs during open load situations.

Though the addition of the above resistor affects the efficiency a bit, it superbly improves voltage regulation response of the circuit.

The rectifier diodes fixed at the output are fast response fast recovery types. D1 is a high voltage diode as it might be subjected to high reverse voltages delivered by the DC bus voltage...... D2 is a normal diode.


Parts List for the proposed simple SMPS buck converter circuit:


Rr = 10W 1/2W
Rf = 10KW 1/4W
Rburden = 4.7kW 1/4W
Cin = 4.7 μF, 450V Electrolytic Capacitor
C1 = 33 μF, 50V Electrolytic Capacitor
C2 = 100 μF, 16V Electrolytic Capacitor
C3 = 1 μF, 25V Electrolytic Capacitor
C4 = 22 nF Ceramic capacitor
Dr = Diode 1N4007
D1 = Diode BA159 (fast)
D2 = Diode 1N4148 (fast)
D3 = Diode 1N4004
Dz = 22V Zener
Dz1 = 27V Zener
Dz2 = 5.6V Zener
L 1 = 0.5 mH
Lf = 470 μH Inductor
IC1 = STMicroelectronics VIPer12ADIP

PCB Design and Component Layout of the above explained SMPS buck converter circuit using IC VIPer12A





Complete Article can be found here

Need Help? Please leave a comment, I'll get back soon with a reply!




Comments

  1. hello,
    can you please help me modify this circuit to get the output voltage at 110v , including the ferrite core transformer design if possible
    thanks in advance

    ReplyDelete
  2. hello, the above circuit is designed to work right from 85V to 285V, so the same design could be used for 110V too.

    ReplyDelete
  3. what i meant was to obtain 110V output instead of 12V from 220V mains input

    ReplyDelete
  4. no, the above circuit cannot be modified for 110V, you can try it in the following circuit:
    3.bp.blogspot.com/-Jbp0LrP-PlU/UxWFwYeF2ZI/AAAAAAAAGaM/kRgOicbzIaE/s1600/12v+5+amp+transformerless+battery+charger+circuit.png

    the output winding may be made by winding 50 turns and the zener replaced by a 140V zener

    ReplyDelete
  5. thanks a lot for the input,
    what i am actually trying is to make an inverter which has :-
    input:220v ac 50Hz
    output:110V ac 800-1000Hz
    right now i am trying a half bridge inverter with mosfets and capacitor divider.
    can u suggest some good circuits?

    thanks in advance

    ReplyDelete
  6. The circuit would be basically the same as suggested in my previous email since the input is 220V.

    However the output frequency will be equal to the input mosfet frequency at around 60kHz which unfortunately cannot be changed to 1000Hz. you may have to employ another stage at the 110V output stage of the circuit for enforcing it.

    ReplyDelete
  7. Hello
    can you wright an explanation how this circuits start to work ( IC VIPer12A )

    ReplyDelete
  8. hello,
    you can refer to the datasheet of the IC for the details.

    ReplyDelete
  9. hello,
    can you please help me how to current increase without changing voltage
    thanks in advance

    ReplyDelete
  10. current cannot be increased, 50mA is the maximum limit of the mentioned IC.

    you may have to change the IC with a VIPer22a for getting 250mA...

    more info is furnished here:

    www.st.com/web/en/resource/technical/document/application_note/CD00004329.pdf

    ReplyDelete
  11. Hello Sir,i am making a buck converter in analog domain without using any IC's.I have used an astable multivibrator for generating the squarewave(350khz) required for switching the Mosfet on and off.The problem was with the gate driver circuit required for mosfet.i used a complementary symmetry push pull amplifier(using BJT) as the Gate Driver.But this driver circuit was not switching the mosfet ON and OFF.Instead it keep the Mosfet ON continuously.Suggest me ways to overcome it and also give me advice on how to provide automatic feedback for keeping the output voltage constant at 9v irrespective of Input voltage Variation(Line Regulation) and Load Change(Load Regulation).Please Do help me out

    ReplyDelete
  12. Hello Sam, without seeing the design it would be difficult for me to assess the fault and suggest an appropriate solution, if possible show me the schematic by uploading the image on Google drive or any other free image hosting site and provide the link to me....

    ReplyDelete
  13. hello sir, currently i am trying to get 13V 4Amp DC from 19V 4.5Amp DC input....i tried voltage divider cct but at the end found out buck converter to be the possible solution.......

    I am avoiding LM317 with resistor network.....as i fear its O/P may vary if resistor got burned ...........

    could u plz suggest the buck converter design ......??

    is cct in this article could be modified to get 13V O/P........??

    ReplyDelete
  14. Hello Muhammad,

    You can try the following circuit:

    https://homemade-circuits.com/2015/05/5v-pwm-solar-battery-charger-circuit.html

    you can alter R8, R9 values for getting the desired output

    ReplyDelete
  15. ...for 4amp load LM317 will not work, you can try LM338 instead.

    ReplyDelete
  16. So nice of you Sir, I will check feasibility of both and will be back with results soon.........:))

    ReplyDelete
  17. please remove this circuit as beginners may think it is working.

    ReplyDelete
  18. Ofcourse it is working.

    it is a wonderful circuit, I have tested it myself

    ReplyDelete
  19. Hello Sir,

    Possible to design viper50 or viper 100. smps circuits. output is dual 15V @2amp. i need to power-up my preamp mixer.

    thanks

    ReplyDelete
  20. Hello Odie, the part values for the Viper100 circuit has not been properly detailed in the datasheet of the IC, I will have to study and then estimate the part values, so that might take some time.

    in the meantime you could try the following design instead

    https://homemade-circuits.com/2014/06/smps-2-x-50v-350w-circuit-for-audio.html

    the output winding turns could appropriately reduced for getting the required 15V

    ReplyDelete
  21. hi what modification need in above circuit to get 4.2V 2Amp as out put from 230V ac

    ReplyDelete
  22. You can slightly adjust the number of turns on the side of the inductor which is associated with the 5V output....or simply add a 1N4007 diode in series with the 5V output to get the required 4.2V approximately.

    ReplyDelete
  23. is it related to inductor wire guage

    ReplyDelete
  24. it is related to number of turns not gauge, gauge is related to current...

    ReplyDelete
  25. yes sir for 2 Amp current i need to change winding guage i think and for voltage as you said i use diode

    ReplyDelete
  26. sorry, I just forgot to tell you that 2 amp may not be possible with this circuit, the maximum current is 250mA for this design
    you can try this instead

    https://www.homemade-circuits.com/12v-2-amp-smps-circuit/

    ReplyDelete
  27. how to make only one 12V 1A(approx) usinh this ic.

    ReplyDelete
  28. try replacing the IC with viper22A, as used in this design

    https://www.homemade-circuits.com/how-to-make-simple-12-v-1-amp-switch/

    ReplyDelete

Post a Comment